The issue of weighting a cue was recently proposed by Jason Owen on this forum. I don’t know how any of the cuemakers approach this and achieve this with any accuracy but this is just a method that I came up would after due consideration of the problem. It would be nice to get some insight from others as to what their experience (if any) with this particular problem is. I could think of two approaches to weighting and balancing a cue. The first would be a calculated approach. Being lazy I would go via this method but mistakes can happen with calculations unless one is good with physics and mathematics. The second would be a simple hands-on exercise with almost very little chance of making a mistake. A piece of fishing line and a plastic bank coin packet or ziplock bags would do and lead.
Generally after a cue is finished it is weighed and thereafter the cuemaker would weigh the cue and check for its unweighted balance point. From this point the cuemaker can determine what weight he requires of the cue and how far from the butt he requires a balance point. Once the weight required is determined the cuemaker then determines how much lead (generally this is used for a number of reason mainly because it’s has a high density which is 11.34g/cm3) to be used. Weighing out this amount of lead the cuemaker can then place that amount in a ziplock or bank coin packet and seal the contents. Measuring the distance from the end of the butt that the new balance point would be, this point is marked in pencil on the cue. The ziplock bag is then tied on one end of the fishing line and on the other end is a slipknot. Place the cue on a Fulcrum (Eg an outstretched finger) and noting which side the cue dips. On the opposite side of the fulcrum place the bag with lead tied to the slipknot along the shaft of the cue. And move along like on some scales till one gets the cue being horizontal with no bias to one side or another. Mark that spot where the slipknot is on the cue with a pencil mark. This would represent where the CENTRE OF MASS OF LEAD would be positioned. I am highlighting this as it is very important. When one drills a hole in the buttend of a cue and say for example one wanted an increase of two ounces of lead. This would mean approximately 56.7 grams of lead. That would mean 5 cm3 (by formula of mass divided by density = 56.7 grams lead/11.34g/cm3) of lead would have to be used to weight the cue to the desired mass. Suppose a hole of 1cm diameter was drilled all the way up the cue. This would mean that the length of 6.4 cm of SOLID LEAD (not lead pellets) cylinder with a diameter of 1 cm would be needed to be inserted into the butt end of the shaft. The length of the hole that is drilled would need to be 3.2 cm past the mark of the slipknot where the cue balanced on the fulcrum previously described. The reason for this is that the centre of mass of the lead cylinder needs to sit on the exact location of the slipknot pencil mark.
One last note is that the mass of the wood that the lead displaces would be approximately 2/3 the volume(cm3) to give the number of grams extra lead that needs to be added to the mass. This may seem confusing but it is important if one wants to be accurate to within a gram. So as a rule of thumb when weighting the cue for each additional inch of lead drill 0.1cm extra or deeper and add 0.2cm more lead(for a 1 cm diameter cylinder lead pellet) so that our final weighting would be in this case 3.3 cm past the line of the slipknot mark with a lead cylinder pellet of 6.6 cm. For those that find this a bit confusing I have added the following drawing. Hope this clears it up some. After inserting the lead pellet the drilled hole is seal of with a dowl.
For a one piece cue the drilling depth would be significantly larger than for a ¾ or centre joint as I would imagine due to the one piece being solid and the drilling site is always from the butt end. With a ¾ it would be much easier to weight I suppose. Also the hole that is being drilled has to be dead centre else one would end up with a situation of a gravity cue ie where the cue always ends up resting at one position even when left on a table.
Generally after a cue is finished it is weighed and thereafter the cuemaker would weigh the cue and check for its unweighted balance point. From this point the cuemaker can determine what weight he requires of the cue and how far from the butt he requires a balance point. Once the weight required is determined the cuemaker then determines how much lead (generally this is used for a number of reason mainly because it’s has a high density which is 11.34g/cm3) to be used. Weighing out this amount of lead the cuemaker can then place that amount in a ziplock or bank coin packet and seal the contents. Measuring the distance from the end of the butt that the new balance point would be, this point is marked in pencil on the cue. The ziplock bag is then tied on one end of the fishing line and on the other end is a slipknot. Place the cue on a Fulcrum (Eg an outstretched finger) and noting which side the cue dips. On the opposite side of the fulcrum place the bag with lead tied to the slipknot along the shaft of the cue. And move along like on some scales till one gets the cue being horizontal with no bias to one side or another. Mark that spot where the slipknot is on the cue with a pencil mark. This would represent where the CENTRE OF MASS OF LEAD would be positioned. I am highlighting this as it is very important. When one drills a hole in the buttend of a cue and say for example one wanted an increase of two ounces of lead. This would mean approximately 56.7 grams of lead. That would mean 5 cm3 (by formula of mass divided by density = 56.7 grams lead/11.34g/cm3) of lead would have to be used to weight the cue to the desired mass. Suppose a hole of 1cm diameter was drilled all the way up the cue. This would mean that the length of 6.4 cm of SOLID LEAD (not lead pellets) cylinder with a diameter of 1 cm would be needed to be inserted into the butt end of the shaft. The length of the hole that is drilled would need to be 3.2 cm past the mark of the slipknot where the cue balanced on the fulcrum previously described. The reason for this is that the centre of mass of the lead cylinder needs to sit on the exact location of the slipknot pencil mark.
One last note is that the mass of the wood that the lead displaces would be approximately 2/3 the volume(cm3) to give the number of grams extra lead that needs to be added to the mass. This may seem confusing but it is important if one wants to be accurate to within a gram. So as a rule of thumb when weighting the cue for each additional inch of lead drill 0.1cm extra or deeper and add 0.2cm more lead(for a 1 cm diameter cylinder lead pellet) so that our final weighting would be in this case 3.3 cm past the line of the slipknot mark with a lead cylinder pellet of 6.6 cm. For those that find this a bit confusing I have added the following drawing. Hope this clears it up some. After inserting the lead pellet the drilled hole is seal of with a dowl.
For a one piece cue the drilling depth would be significantly larger than for a ¾ or centre joint as I would imagine due to the one piece being solid and the drilling site is always from the butt end. With a ¾ it would be much easier to weight I suppose. Also the hole that is being drilled has to be dead centre else one would end up with a situation of a gravity cue ie where the cue always ends up resting at one position even when left on a table.
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