...what would happen if the following (unlikely) scenario occurred:
A player pots (for arguments sake) 5 reds and 4 blacks and is snookered on the 5th black. He attempts to hit the black but is unsuccessful, and a 'miss' is consequently called. The opposing player doesn't have anything easy on and so has the balls replaced, but this time the original player not only gets out of the snooker, but flukes the black as well!
Would this be the start of the break (i.e. 7) or would it continue on from his previous effort and he'd be on for a 147??
I think I know the answer...it would just seem odd if a break was to begin with someone potting the black!!
Thanks,
Rich
A player pots (for arguments sake) 5 reds and 4 blacks and is snookered on the 5th black. He attempts to hit the black but is unsuccessful, and a 'miss' is consequently called. The opposing player doesn't have anything easy on and so has the balls replaced, but this time the original player not only gets out of the snooker, but flukes the black as well!
Would this be the start of the break (i.e. 7) or would it continue on from his previous effort and he'd be on for a 147??
I think I know the answer...it would just seem odd if a break was to begin with someone potting the black!!
Thanks,
Rich
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