If, having potted a colour, a player strikes the cueball while aiming at the next red before the coloured ball has been respotted by the referee, is this deemed a foul? If the colour in question is blue, pink, or black, are five, six or seven points respectively awarded to the opponent?
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Snooker rules - respotted colours
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Yes, it would be a foul since he has fouled the cueball before the colour has been replaced and therefore it would be the value of that colour. His next shot doesn't really commence until the colour has been properly re-spotted so he has committed a foul whilst that colour was still in play. I imagine one of the referees will be able to quote the specific rule for you
TerryTerry Davidson
IBSF Master Coach & Examiner
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Yes, it would be a foul, as Terry says.
The penalty would be the value of the ball on (which is the ball on for the shot just played, as that stroke has not yet been completed).
To be pedantic, the 2011 rule book now speciifies the penalty as the ball on where the colour which hasn't been respotted was taken as a free ball. It goes on to say that the penalty in other cases is the value of the ball on or ball concerned, whichever is higher, although I'm at a loss to think of any time that the penalty will be other than the value of the ball on, except in one very odd scenario. That scenario is when, say blue, pink and black are left on the table, and player pockets blue but doesn't realise he's been called for a foul, and goes on to play at the pink before the blue has been respotted.
The new rule do mean that if, say pink is taken as a free ball when red is on, then striking at black before the pink is respotted will give rise to a penalty of just four (as red was still the ball on for the stroke in which the black was played at!).
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Originally Posted by Souwester View PostYes, it would be a foul, as Terry says.
The penalty would be the value of the ball on (which is the ball on for the shot just played, as that stroke has not yet been completed).
To be pedantic, the 2011 rule book now speciifies the penalty as the ball on where the colour which hasn't been respotted was taken as a free ball. It goes on to say that the penalty in other cases is the value of the ball on or ball concerned, whichever is higher, although I'm at a loss to think of any time that the penalty will be other than the value of the ball on, except in one very odd scenario. That scenario is when, say blue, pink and black are left on the table, and player pockets blue but doesn't realise he's been called for a foul, and goes on to play at the pink before the blue has been respotted.
The new rule do mean that if, say pink is taken as a free ball when red is on, then striking at black before the pink is respotted will give rise to a penalty of just four (as red was still the ball on for the stroke in which the black was played at!).
As is usually the case, nominating pink as a free ball means that a foul of 6 points is impossible because there is no ball on the table with a value of 6.
Of course, if the player 'pots' the black, then the penalty would be seven, the higher value of the two fouls - playing before the referee has spotted a colour (essentially hitting the cue-ball more than once during the same stroke) which is 4 and pocketing the black when not a ball on which is 7.
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To answer the original question further - Yes it is a foul on the 'previous' stroke, meaning that the player does not score for the colour he potted. For example:
First shot - player pots red - referee calls 1
Second shot - player 'pots' blue
Third shot - player 'pots' red but does so before the referee has spotted the blue.
The referee calls Foul 1 scored, 5 away. The foul has occurred on the second shot, not the third (in fact, no third shot has technically taken place).
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