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got more meanwhile 3....9411764705882
hope avoided typos,
got to pick the kid, see you in an hour or so
Interesting... it looks like you're missing some digits from the end and you've got some random digits put at the start that shouldn't be there...
There's some good stuff in the middle though
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
You play a long slow deadweight red to a corner pocket. As it approaches the pocket, a kamikaze woodlouse crawls out from under the cushion and makes its way across the table, conflicting with the path of the red precisely at the point the red gets there. The red, needless to say, veers off course, and the future of the woodlouse is uncertain. - The Statman
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
That's right. So, it's like the 285,714 - where putting the last digit at the start multiplied the whole number by 1½ - except this time you need to put the first digit on the end (in order to multiply the whole number by 1½)!
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
Get rid of the 94 at the start. Then you have most of the number, but missing the last few digits...
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
The question is too confusing for me, I could even start to work out an answer
You play a long slow deadweight red to a corner pocket. As it approaches the pocket, a kamikaze woodlouse crawls out from under the cushion and makes its way across the table, conflicting with the path of the red precisely at the point the red gets there. The red, needless to say, veers off course, and the future of the woodlouse is uncertain. - The Statman
Clive did indeed give Petdon an astonishing 1176470588235294 smacks.
If you move the first digit to the end, you get 1764705882352941, which is 1½ times the original number. This is the smallest number that this works for.
The number of smacks I gave Shirty (285714) is the first 6 digits of the decimal expansion of 2/7 = 0.285714…. and if you move the last digit to the start, you get the first 6 digits of the decimal expansion of 3/7 = 0.428571...
1176470588235294 is the first 16 digits of the decimal expansion of 2/17 = 0.1176470588235294…
If you move the first digit to the end, you get the first 16 digits of the decimal expansion of 3/17 = 0.1764705882352941…
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
had I only known about expansions... , guess I did it the hard way again...
Originally Posted by davis_greatest
Congratulations, snookersfun!
The number of smacks I gave Shirty (285714) is the first 6 digits of the decimal expansion of 2/7 = 0.285714…. and if you move the last digit to the start, you get the first 6 digits of the decimal expansion of 3/7 = 0.428571...
1176470588235294 is the first 16 digits of the decimal expansion of 2/17 = 0.1176470588235294…
If you move the first digit to the end, you get the first 16 digits of the decimal expansion of 3/17 = 0.1764705882352941…
btw. is there a way to not have excell rounding your last digits in such long numbers?
If there is, I would like to know it!
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
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