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Round 163.... OK, I've had some right and some wrong answers... for those still trying, here are some more (big ) clues:
If a triangle has n rows, then it has n(n+1)/2 balls.
(For example, a triangle of reds in snooker has n=5 rows, and 5 x 6 / 2 = 15 balls.)
Now each "triangle" has 1 ball missing, so it has n(n+1)/2 - 1
= (n² + n - 2)/2 balls
So the two "triangles" (each with a ball missing) comprise (n² + n - 2) balls in total.
We can factorise this as
(n² + n - 2) = (n - ?)(n+ ?)
131 by 1129. So then, I have to find the number of balls left in the Rectangle. So, we have 1129 balls, from 1 line. So, The number of balls in the rectangle has to be even.
So if you've got, 147.899kg then you have 147,899 grams. You also have to find a (triangular number -1)*2. Triangle Numbers are 1, 3, 6, 10, 15 ect. So I'm looking for a number that , 0, 2, 5, 9 ect.
Am I on the right lines?
Yes, 147899 grams and yes, you're on the right lines
Yes, the number of balls in each "triangle" (with one ball missing) could be 2, 5, 9 etc. Remember there are 2 triangles, so there will be twice as many balls as that. And then all the balls are placed in a rectangle, longer that it is wide, but as wide as possible.
You need to find the factors of 147899. Then one row of balls weighs 147899 grams, so the number of balls in a row of the rectangle is.... ?
So if you've got, 147.899kg then you have 147,899 grams. You also have to find a (triangular number -1)*2. Triangle Numbers are 1, 3, 6, 10, 15 ect. So I'm looking for a number that , 0, 2, 5, 9 ect.
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