From the sequence of hexagonal numbers 7,19,37,61....
Does anyone remember how to expand :
n = 1 + SUM(6n) {n=1:n}
to f(n) = 1+ 3(n+1)(n)..
And after that, sum the sequence again to get to
n = (n+1)^3 -1.
Snookersfun?
Does anyone remember how to expand :
n = 1 + SUM(6n) {n=1:n}
to f(n) = 1+ 3(n+1)(n)..
And after that, sum the sequence again to get to
n = (n+1)^3 -1.
Snookersfun?
Comment