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  • hegeland
    replied
    Sorry, my mistake, davis_greatest gets the point!

    I had mistyped when converting fathoms into meters.
    8.3552056 fathoms = 1528 centrimeters but the answer I was looking for should be 1828 centrimeters. Im sorry!

    This is how you solve it anyway; Im sure this is how davis_greatest did it, just using 15.28 m instead of 18.28 m.

    You got two equations:

    1. 18.28 = V0 * cos (42°) * t
    => V0 = 18.28 / (cos (42°) * t)

    2. -2.1 = (V0 * sin (42°) * t) - ((9.82 * t2) / 2)


    Put them together and you get:

    -2.1 = ((18.28 * sin (42°)) / (V0 * cos (42°))) - ((9.82 * t2) / 2)


    After some simplification you get:

    -2.1 = 16,46 - (4.91 * t2)

    t = 3.780 ^ (1/2) = 1,944 seconds


    Then put in your t in equation 1

    V0 = 18.28 / (cos (42°) * 1,944) = 12.65 m/s ≈ 12.7 m/s

    Sorry, man!

    Leave a comment:


  • hegeland
    replied
    Originally Posted by davis_greatest
    I may have misunderstood the question then... because I was sure my answer was correct when I did it in a couple of different ways last night. I'll wait to see your solution - perhaps you can PM it to me?...
    Sure can. But anyone who wants to take a guess may do so. I'll post the solution on here later too.

    Leave a comment:


  • davis_greatest
    replied
    Originally Posted by hegeland
    Nope, sorry, that's not correct. You'll get a few more chances since no one else have bothered to answer - yet.
    I may have misunderstood the question then... because I was sure my answer was correct when I did it in a couple of different ways last night. I'll wait to see your solution - perhaps you can PM it to me?...

    Leave a comment:


  • hegeland
    replied
    Sorry, 500m/s is not correct. You may now have more than one attempt to answer.

    Leave a comment:


  • chasmmi
    replied
    498.759m/s

    Leave a comment:


  • hegeland
    replied
    Nope, sorry, that's not correct. You'll get a few more chances since no one else have bothered to answer - yet.

    Leave a comment:


  • davis_greatest
    replied
    Originally Posted by hegeland
    Can I post a question?

    ROUND 65

    An frustrated snooker player (Statman ) throws away the brown ball after having missed an easy double into the left middle pocket. The ball lands on the floor between two tables 8.3552056 fathoms further away. The throw form an angle of 0.733038 radians with the horizontal plane. Assume the ball leaves his hand at 0.010439036 furlongs height. Ignore air resistance. Gravity about 9,82 m/s2.

    With what initial velocity did Statman throw the ball? (meters/second)

    NOTE: ONE GUESS PER PERSON. NO PM's please, my inbox is full.
    How well did Davis play to beat Doherty 5-1? Unfortunately I missed it, as I was at work and then out this evening playing snooker myself. I am recording the replay tonight though.

    Anyway... to answer hegeland's question:
    11.441 metres per second, at an angle of 0.733038 radians with the horizontal plane

    Leave a comment:


  • snookersfun
    replied
    now this is a really mad question, if I may say so

    and psssst, Hege, you can/should delete from your Inbox (download the good ones for safe-keeping if you have difficulties parting with them

    Leave a comment:


  • hegeland
    replied
    Originally Posted by davis_greatest
    Sorry - still slighly confused, on the new wording... does it land at table height or does it land at floor height, i.e. 0.010439036 furlongs below Statman's hand?
    See question.

    Leave a comment:


  • davis_greatest
    replied
    Originally Posted by hegeland
    Can I post a question?

    ROUND 65

    An frustrated snooker player (Statman ) throws away the brown ball after having missed an easy double into the left middle pocket. The ball lands between two tables 8.3552056 fathoms further away. The throw form an angle of 0.733038 radians with the horizontal plane. Assume the ball leaves his hand at 0.010439036 furlongs height. Ignore air resistance. Gravity about 9,82 m/s2.

    With what initial velocity did Statman throw the ball? (meters/second)

    NOTE: ONE GUESS PER PERSON. NO PM's please, my inbox is full.
    Sorry - still slighly confused, on the new wording... does it land at table height or does it land at floor height, i.e. 0.010439036 furlongs below Statman's hand?

    Leave a comment:


  • hegeland
    replied
    Originally Posted by davis_greatest
    We need an assumption for gravity too, don't we? ... what should we use: 9.81 metres per second squared?
    Sorry again, see question.

    Leave a comment:


  • davis_greatest
    replied
    We need an assumption for gravity too, don't we? ... what should we use: 9.81 metres per second squared?

    Leave a comment:


  • hegeland
    replied
    Originally Posted by davis_greatest
    2 more questions:

    1) what do you mean "the throw measures" ... is this the horizontal distance travelled by the ball from Statman's hand until it lands?

    2) Do we ignore air resistance? I assume so...
    Sorry, I've rewritten it a bit now.

    Leave a comment:


  • davis_greatest
    replied
    Originally Posted by hegeland
    Can I post a question?

    ROUND 65

    An frustrated snooker player (Statman ) throws away the brown ball after having missed an easy double into the left middle pocket. The throw measures 8.3552056 fathoms. The throw form an angle of 0.733038 radians with the horizontal plane. Assume the ball leaves his hand at 0.010439036 furlongs height.

    With what initial velocity did Statman throw the ball?
    2 more questions:

    1) what do you mean "the throw measures" ... is this the horizontal distance travelled by the ball from Statman's hand until it lands?

    2) Do we ignore air resistance? I assume so...

    Leave a comment:


  • davis_greatest
    replied
    And in what units would you like the answer? Inches per hour, or chains per lunar year?

    Leave a comment:

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