Puzzles with numbers and things

[davis_greatest]

Oh, another nice round finished before I've even seen it...

abextra, both rounds are still open - I was just giving an update of who had answers in already.

[abextra]

Round 369 - Countdown Breakdown

Use the 13 snooker balls below, and any combination of addition, subtraction, multiplication or division to make the following three target snooker numbers: 100, 147 and 155.

Oh, another nice round finished before I've even seen it...

Just waiting for abextra once ready to post her list of colours...

... and of course anyone else who wants to put up a bid!

abextra is late again... probably my solution is posted already...
(starting with free ball) 2 2 4 7 6 5 7 6 3 7 5 6 7 2 4 7
or 2 2 3 7 6 4 7 6 5 7 2 6 7 5 4 7
+ final colours

[Monique]

R368

Hope I didn't mess it up this time ...
2,2,4,7,6,5,7,6,3,7,5,6,7,2,4,7 and the colours for 123

[moglet]

R369

Are Brackets OK?:

5x5x4=100,7x7x3=147,(2x7)x(7+5-1)+(2-1)=155

[moglet]

R368

Would this do:

223,765,764,752,764,7 (123)

[moglet]

Thanks moglet! Unfortunately you can't start with a black because then you would have scored 7 points with blacks after the first colour .... the total value of all lower-valued colours potted by that point would be 0 - and that isn't allowed as 7 exceeds 0.

Whoops!, will try again.....

[davis_greatest]

Thanks moglet! Unfortunately you can't start with a black because then you would have scored 7 points with blacks after the first colour .... the total value of all lower-valued colours potted by that point would be 0 - and that isn't allowed as 7 exceeds 0.

[moglet]

R368

Two more bids here

Without free ball 755,467,267,267,367 (122) With free ball 755,637,247,267,267,4 (123)

[davis_greatest]

Meanwhile, update from round 369 - correctly solved so far by snookersfun and Monique - congratulations.

Rounds 368 and 369 both still open.

[Monique]

Sorry. I didn't read properly. I thought that rule applied also only from third colour on. My mistake.

[davis_greatest]

it's not the second, it's the third ... having potted yellow and pink first. That's 8. BTW .. I start with a free ball there.

Oh sorry - I meant pink, rather than black. But you can't pot pink as second colour either, because pink is worth 6, which exceeds the value of your first yellow (2).

[Monique]

it's not the second, it's the third ... having potted yellow and pink first. That's 8. BTW .. I start with a free ball there.

[davis_greatest]

Round 368 - update

snookersfun, congratulations on your bid, which works!

Monique - please check yours - your 2nd colour seems to break the rules? You can't pot black as your 2nd colour, because you would have scored 7 points with blacks at that point, which exceeds the points you have by then scored with the other lower valued colours. Edit after Monique's post below: that previous sentence should read: "You can't pot pink as your 2nd colour, because you would have scored 6 points with pinks at that point, which exceeds the points you have by then scored with the other lower valued colours."

Just waiting for abextra once ready to post her list of colours...

... and of course anyone else who wants to put up a bid!

[Monique]

Here is it again... it's the same as the one I deleted I'm not quite awake today!

155=((7+7+2-1)*2 +1)*5
147=7*7*3
100=5*5*4

[snookersfun]

and now, in the right place:
found one:

(7-2)x5x4=100; 3x7x7=147; 5x(5x(7-2+1)+1)=155 :snooker: