Puzzles with numbers and things

[Monique]

But to reach 155 Rollie would need a free ball anyway ... how can he get that if Grott is not fouling? Or am I totally confused?

[snookersfun]

But to reach 155 Rollie would need a free ball anyway ... how can he get that if Grott is not fouling? Or am I totally confused?

oops, yes, see that now wouldn't work, would it?

[davis_greatest]

oops, yes, see that now wouldn't work, would it?

No, it wouldn't.

OK, let me give a clue.... Rollie makes many fouls prior to his record run of unanswered unanswered points. Does that help?

[snookersfun]

No, it wouldn't.

OK, let me give a clue.... Rollie makes many fouls prior to his record run of unanswered unanswered points. Does that help?

respotted black in that first frame? as score was 155-155 after the many foul shots?

so 309 altogether?

[davis_greatest]

respotted black in that first frame? as score was 155-155 after the many foul shots?

so 309 altogether?

Yes, 309!!! Congratulations!

So, more or less there... of course, it can't be 155-155 though - so, what could the score have been?

[davis_greatest]

Enough of round 315 - the answer, as snookersfun has stated, is 309. One way would be if Rollie conceded 159 points in fouls at the start of the frame, and Grott then fouled (4), leaving a free ball. Rollie then made a 155, won the toss and potted the respotted black, and broke off, making a 147 in the following frame.

Round 316 - 36-ball maximum?

Playing Rollie in the next round, Dave Stevis played 36 consecutive shots during the match without Rollie getting to the table - Stevis potting during every one of those shots.

What is the greatest total number of points that Stevis could have scored during those 36 shots?

Please put bids directly on the thread...

[R_Demarco]

I go for 152 in a normal match.

green, brown, blue, pink, black, respotted black. (next frame) 15 reds and black.

Or in theory, 221.

blue, pink, black, respotted black = 25 (4 shots)
15 reds all potted in one shot, black and colours = 49 (8 shots)
He does 3 frames more like this. 4x49 = 196. plus the 25 points.

[Monique]

The latter does not work or does it? Because with that scenario Rollie should come at the table to break-off at least twice ...

[snookersfun]

I go for 152 in a normal match.

green, brown, blue, pink, black, respotted black. (next frame) 15 reds and black.

Or in theory, 221.

blue, pink, black, respotted black = 25 (4 shots)
15 reds all potted in one shot, black and colours = 49 (8 shots)
He does 3 frames more like this. 4x49 = 196. plus the 25 points.

not having much time at the moment, but as 2nd option wouldn't work, one could though make a happy mix of your two proposals...
think I got 169 points (excluding foul points) one time (ok 3 times) through now:

how about:
(starting with free ball)
4 reds + black
4*3reds + black
all colours

3reds + black
6*2reds + black
all colours

[R_Demarco]

Yes, you are right!

The latter does not work or does it? Because with that scenario Rollie should come at the table to break-off at least twice ...

[davis_greatest]

snookersfun leads with an excellent 169.

A gentle reminder, also, to any new members who haven't read the whole thread, that answers should not be edited, or will be void. If an answer needs to be changed, the replacement should appear in a new post.

169 is not the highest possible... any new bids?

[snookersfun]

169 is not the highest possible... any new bids?

new idea over lunch. Starting off with free ball red potted by opponent and leaving that mess on the colour/being put back in situation; also needs a lot of foul points by Dave again:

so starting with
black
5x 3 reds with blacks
all colours
respotted black

3x 3 reds with blacks
3x 2 reds with blacks
all colours

and I think that makes 175 now

[davis_greatest]

Very good, snookersfun - and congratulations!

That (or any of a number of variations of it) is what I had - I don't think that 175 can be beaten!

[davis_greatest]

So onto ...

Round 317 - Banana Mad

Little Gordon the gorilla has just turned up for his one-frame match against Maun Shirty with all his usual essential equipment - his cue, extension, his chalk, 17 spare chalks, and a sack of 147 bananas.

Shirty breaks off but after his turn is over, he plays only one further shot during the match. He also does something rather odd whenever Gordon is at the table - for every ball that Gordon pots, Shirty puts three extra bananas into Gordon's sack; however, for every point that Gordon scores by potting balls, Shirty eats one of the gorilla's bananas.

Gordon knows this and chooses his shots wisely, as Shirty always does the same thing whenever they play. So cunning is Gordon, in fact, that it turns out that at the end of the match Gordon is about to leave with the greatest possible number of bananas in his sack. However, it is so heavy that he can barely carry it, so he decides that the best possible thing to do will be to eat the lot. And that is exactly what he does.

How many bananas does Gordon eat at the end of the match?

Please post your bids for numbers of bananas here.

[davis_greatest]

and at the same time as answering round 317, please put bids for round 318, which is similar but has strawberries.

Round 318 - Strawberry Surprise

During the same match in round 317, exactly the same thing happens with Gordon's other sack, initially containing 147 strawberries - except that for every ball that Gordon pots, Shirty puts two (not three) strawberries into Gordon's sack (and eats one of Gordon's strawberries for every point that Gordon scores by potting balls).

What is the maximum number of strawberries that Gordon can have at the end of the match?

Please post your bids for numbers of strawberries (round 318) at the same times as answering round 317 (bananas).