Puzzles with numbers and things

[davis_greatest]

I've changed my mind back to 5 (ignore the comment above about 6) - but I'm still not certain that it can't be bettered

[snookersfun]

I've changed my mind. I think that at least 6 is possible. What I'm not sure, without attacking this problem properly, is whether more is possible - e.g. perhaps all 11 balls from the others, perhaps by some kind of spiral formation.

looking forward to the set-up

[davis_greatest]

now that sounds promising

I've changed my mind. I think that at least 6 is possible. What I'm not sure, without attacking this problem properly, is whether more is possible - e.g. perhaps all 11 balls from the others, perhaps by some kind of spiral formation.

[snookersfun]

the only ones who could do that (Oliver, Charlie, Gordon) are more interested in bananas than (half)points!

(of course, I meant DGs photo)

anybody willing to donate bananas then? Although I doubt that these three are your regular banana bunch (they seem to have quite a few other interests). Also, we know, that D_G started to manage to upload pictures, Avatars and stuff recently.

[April madness]

well, how would I know otherwise? Can I offer half points (for anybody having successfully answered on this thread) for putting his picture up in the gallery?

the only ones who could do that (Oliver, Charlie, Gordon) are more interested in bananas than (half)points!

(of course, I meant DGs photo)

[snookersfun]

OK, where's my centrepoint? Do you think I look like a snooker ball?

(No need to answer that)

well, how would I know otherwise? Can I offer half points (for anybody having successfully answered on this thread) for putting his picture up in the gallery?

[snookersfun]

Is more than 5 possible (treating the people / apes as points in 2 dimensions)?

now that sounds promising

[davis_greatest]

Is more than 5 possible (treating the people / apes as points in 2 dimensions)?

[davis_greatest]

, before you ask again, let's take the distances as from centerpoint to centerpoint.
Any further questions, just shoot

OK, where's my centrepoint? Do you think I look like a snooker ball?

(No need to answer that)

[snookersfun]

OK... and should we imagine that the guests and Oliver are "points" (i.e. dots of zero size)? Because otherwise, Oliver could easily have the 11 others all touching various parts of him without any of them touching each other, so he would receive 11 balls.

are we playing 10 questions?
How can you fit 11 people/apes around Oliver without touching eachother (we are not stickfigures, aren't we). Also the guests are supposed to have some distance from eachother (all different- but not zero). And probably, before you ask again, let's take the distances as from centerpoint to centerpoint.
Any further questions, just shoot

[davis_greatest]

let's just say 2 dimensional, but I will give extra points for a solution for a 3-dimensional situation

OK... and should we imagine that the guests and Oliver are "points" (i.e. dots of zero size)? Because otherwise, Oliver could easily have the 11 others all touching various parts of him without any of them touching each other, so he would receive 11 balls.

[snookersfun]

let's just say 2 dimensional, but I will give extra points for a solution for a 3-dimensional situation

[davis_greatest]

randomly

So, you mean, not in a ring? Are they in a 2 dimensional horizontal plane or could we have, say, one above another?

[snookersfun]

So how are they positioned?

randomly

[davis_greatest]

ROUND 54:

You are invited to a party.

You are the first to arrive, so at that time there is just you and the host. Gradually, and individually, other invitees turn up.

At what point does the chance of any two people at the party sharing a birthday reach 50%?

By which I mean, when the n-1th person arrives the chacne is less than 50%, and when the nth person arrives, the chance has reached/exceeded 50%.

The Statman, has this been answered as intended - and if so, how are you scoring it - or is it still open?