Puzzles with numbers and things

[abextra]

Could somebody please kindly post the answers and explanations to the latest questions
(Rounds 321, 323 - 329)?
Some of them have been opened for three months already! Thanks.

[Monique]

329 just opened a few days ago ... I know of at least one member who's still working on it. So not yet!

[abextra]

329 just opened a few days ago ... I know of at least one member who's still working on it. So not yet!

Oh, I see. That's a good news!
But what about the earlier rounds, Monique? Anyone? Hope the answers are not a secret or something!

[Monique]

Here is the answer for R323 ...

192 384 576
219 438 657
273 546 819
327 654 981

(I had to do it again ... couldn't find my archives!)

[abextra]

Here is the answer for R323 ...

192 384 576
219 438 657
273 546 819
327 654 981

(I had to do it again ... couldn't find my archives!)

Thank you so much, Monique! I misunderstood this question completely.
Sorry for the trouble.

[davis_greatest]

Could somebody please kindly post the answers and explanations to the latest questions
(Rounds 321, 323 - 329)?
Some of them have been opened for three months already! Thanks.

A clue for round 321, then. First find the 15 triangles that give Gwendoline 15 bananas before Barry comes to play. Then find which 4 balls she takes away, to leave herself with 11 bananas and Barry with 4...

A nice picture up here would be great.

[dantuck_7]

Leave R326 open for a while - as I'll have a look at that tomorrow.

[abextra]

A clue for round 321, then. First find the 15 triangles that give Gwendoline 15 bananas before Barry comes to play. Then find which 4 balls she takes away, to leave herself with 11 bananas and Barry with 4...

A nice picture up here would be great.

Hi, d_g, thank you for the clue!

15 is a big number of triangles to make from 10 balls... anyone knows how to get this many?

[snookersfun]

R. 324: Algebra
please find numeric solutions to
a)
-SEND
-MORE
------
MONEY


b) AlFA+BETA+GAMA=DELTA (find one of several possible solutions)

and I just edit in part c) now:

ABCB - DEFC = GAFB
-: ----- + ----- -
DH - x -- AB = -- IEI
-------------------------
GGE +- DEBB = DHDG

the answers to this question are:

a) 9567+1085 = 10652

b) 5705+2485+6595=14785

c) A=3,B=8,C=0,D=1,E=4,F=5,G=2,H=7,I=6

curtesy of Mon's answers fished out of my PMs now

and while at it, the answer to R 325:
The numbers are 2 & 9.

The first line from Oliver means that the numbers cannot both be prime.... and everything follows from there...


leaving R. 326 open, as requested, but did find Mon's answer as well, so no need to redo

[abextra]

Thank you for the answers, Snookersfun!

and while at it, the answer to R 325:
The numbers are 2 & 9.

The first line from Oliver means that the numbers cannot both be prime.... and everything follows from there...

Lol, , not much follows for me...

[Monique]

Thank you for the answers, Snookersfun!
Lol, , not much follows for me...

look at the possible pairs with their sum and products

Gordon: I knew that. The sum is smaller than 14.

means that the sum - that Gordon knows - is associated with "admissible" pairs only. If there was one pair of primes associated with that sum, Gordon could not be certain. And the sum is less than 14 ...

[abextra]

look at the possible pairs with their sum and products

means that the sum - that Gordon knows - is associated with "admissible" pairs only. If there was one pair of primes associated with that sum, Gordon could not be certain. And the sum is less than 14 ...

Oh, okey, it's over my low level...

Thank you so much for your help, ladies!

[Monique]

Oh, okey, it's over my low level...

Thank you so much for your help, ladies!

Awww Abextra I'm sure that's not true!

Ok to be complete... the previous clue still leaves you with more than one possible answer.

But then Oliver says

That I knew and now I do know the numbers.

This means that the product (he knows) can only be decomposed in factors with a sum under 14... and that solves the puzzle.

[abextra]

Thank you for your help again, Monique!
I've been thinking about it - and I'm 100% sure I would never solve this puzzle myself! Well done everyone who understands it!

And so, in five days I've got answers to three rounds already! Not bad!

[davis_greatest]

Hi, d_g, thank you for the clue!

15 is a big number of triangles to make from 10 balls... anyone knows how to get this many?

Take a careful look. A clue - there are two triangles there whose sides are not parallel to any of the sides of the pack of reds