Originally Posted by davis_greatest

OK, then, I tried to go opposite on that last point, i.e. what are the maximum possible pairings, so that no three pairs made up of three players could be in the same socks.
So one could put all the pairs including player A in green socks (16 pairings), after that all the players (naturally excluding A) including B in pink (15 pairings) and the third biggest group with player C in ginger (14 pairings). So far (45 games) you have avoided giving three such pairs the same color of socks.
Now, the moment any other player plays anybody else, it has to be one of the three colors again and accordingly the third pair is found.
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