So onto ...
Round 317 - Banana Mad
Little Gordon the gorilla has just turned up for his one-frame match against Maun Shirty with all his usual essential equipment - his cue, extension, his chalk, 17 spare chalks, and a sack of 147 bananas.
Shirty breaks off but after his turn is over, he plays only one further shot during the match. He also does something rather odd whenever Gordon is at the table - for every ball that Gordon pots, Shirty puts three extra bananas into Gordon's sack; however, for every point that Gordon scores by potting balls, Shirty eats one of the gorilla's bananas.
Gordon knows this and chooses his shots wisely, as Shirty always does the same thing whenever they play. So cunning is Gordon, in fact, that it turns out that at the end of the match Gordon is about to leave with the greatest possible number of bananas in his sack. However, it is so heavy that he can barely carry it, so he decides that the best possible thing to do will be to eat the lot. And that is exactly what he does.
How many bananas does Gordon eat at the end of the match?
Please post your bids for numbers of bananas here.
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Very good, snookersfun - and congratulations!
That (or any of a number of variations of it) is what I had - I don't think that 175 can be beaten!
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Originally Posted by davis_greatest View Post169 is not the highest possible... any new bids?
so starting with
black
5x 3 reds with blacks
all colours
respotted black
3x 3 reds with blacks
3x 2 reds with blacks
all colours
and I think that makes 175 now
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snookersfun leads with an excellent 169.
A gentle reminder, also, to any new members who haven't read the whole thread, that answers should not be edited, or will be void.If an answer needs to be changed, the replacement should appear in a new post.
169 is not the highest possible... any new bids?
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Originally Posted by R_Demarco View PostI go for 152 in a normal match.
green, brown, blue, pink, black, respotted black. (next frame) 15 reds and black.
Or in theory, 221.
blue, pink, black, respotted black = 25 (4 shots)
15 reds all potted in one shot, black and colours = 49 (8 shots)
He does 3 frames more like this. 4x49 = 196. plus the 25 points.
think I got 169 points (excluding foul points) one time (ok 3 times) through now:
how about:
(starting with free ball)
4 reds + black
4*3reds + black
all colours
3reds + black
6*2reds + black
all colours
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The latter does not work or does it? Because with that scenario Rollie should come at the table to break-off at least twice ...
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I go for 152 in a normal match.
green, brown, blue, pink, black, respotted black. (next frame) 15 reds and black.
Or in theory, 221.
blue, pink, black, respotted black = 25 (4 shots)
15 reds all potted in one shot, black and colours = 49 (8 shots)
He does 3 frames more like this. 4x49 = 196. plus the 25 points.Last edited by R_Demarco; 24 February 2008, 11:21 PM.
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Enough of round 315 - the answer, as snookersfun has stated, is 309. One way would be if Rollie conceded 159 points in fouls at the start of the frame, and Grott then fouled (4), leaving a free ball. Rollie then made a 155, won the toss and potted the respotted black, and broke off, making a 147 in the following frame.
Round 316 - 36-ball maximum?
Playing Rollie in the next round, Dave Stevis played 36 consecutive shots during the match without Rollie getting to the table - Stevis potting during every one of those shots.
What is the greatest total number of points that Stevis could have scored during those 36 shots?
Please put bids directly on the thread...
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Originally Posted by snookersfun View Postrespotted black in that first frame?as score was 155-155 after the many foul shots?
so 309 altogether?
So, more or less there... of course, it can't be 155-155 though - so, what could the score have been?
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Originally Posted by davis_greatest View PostNo, it wouldn't.
OK, let me give a clue.... Rollie makes many fouls prior to his record run of unanswered unanswered points. Does that help?as score was 155-155 after the many foul shots?
so 309 altogether?
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Originally Posted by snookersfun View Postoops, yes, see that nowwouldn't work, would it?
OK, let me give a clue.... Rollie makes many fouls prior to his record run of unanswered unanswered points. Does that help?
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Originally Posted by Monique View PostBut to reach 155 Rollie would need a free ball anyway ... how can he get that if Grott is not fouling? Or am I totally confused?wouldn't work, would it?
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But to reach 155 Rollie would need a free ball anyway ... how can he get that if Grott is not fouling? Or am I totally confused?
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Originally Posted by Monique View PostSo I ruled that out ...
and also because if that's allowed there's no limit... why stop at two frames? If Grott can come at the table to foul why not to break-off?
Unless he fouls without taking a shot? moving ball with his hands
well, theoretically Dott could put Ronnie back in without 'coming to the table'
(whatever coming to the table really implies- could be taking a shot, or might just be his turn to take a shot?)
anyway highly confusing
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