Puzzles with numbers and things

[Monique]

Round 314 ... closing

Congratulations to Abextra, Davis_Greatest and Snookersfun for solving the puzzle!

Would anyone put his/her solution on the thread ...

[snookersfun]

In the meantime...


I've found a sequence

1 - 10 - 10 - 2 - 3 - 10 - 6 - 4

Is my logic OK?

yes, looking good

[abextra]

In the meantime...

I like to add one little easy puzzle. . (cramped for time to solve any at this moment )

once, neat, rent, town, either, vent, axis, flour.

Find the logic and the word hidden in the above list?

I've found a sequence

1 - 10 - 10 - 2 - 3 - 10 - 6 - 4

Is my logic OK?

[Monique]

Round 314 - Highly divisible breaks ...

Andorra Pot Black is a mundane little invitational event where the provisional top three play a little league between them, best of one format.
Uncharacteristically this time Rollie O'Sunnyman didn't decline, most probably because the Andorra Cross took place later on the very same day ...
Rollie had borrowed D_G's apes indivisibility cloak but then Mr. Leygang, the tournament's director judged this was against the dress code etiquette and he was not allowed to wear it
Rollie nevertheless won his two matches in just one visit however in a rather strange way ...
In the post-matcht he first expressed his feelings about Mr Leygang decision. Unfortunately the broadcast went pants with lots of cracking noises ... judging by Dave Stevis and Paul Jaroott's amused and slightly shocked expressions it's a pity really.
He then said that as he couldn't wear the cloak he had made his breaks higly divisible, meaning every intermediate score in those breaks was divisible by at least one previous intermediate score (yes, Rollie's mathematical skills are way better than his spelling or grammar ). He added he was quite pleased with his break against Moany Churchy as he thought it was the highest possible highly divisible break. As for his break against Stany Meguen it was minimal ... he was in a hurry for the cross.
Jaroott observed that no red in these matches had been potted as a single ball ... "well yeah" said Rollie putting his trainers on. And that's as much as he agreed to elaborate ... the next secong he was running away heading for Andorra cross ...
What were Rollie's breaks and how did he make them?

PS: I'm in Athens relying on Internet cafe ... so answers by PM please and ... patience.

[davis_greatest]

LOL abextra.... great picture. That is exactly how the white looked after its exertions!

[abextra]

Hehehe... I bet the white looks different after such a hard exercise...

[davis_greatest]

Unchanged?

Maybe Any other answers or anyone agreeing with Monique...?

[Monique]

Unchanged?

[davis_greatest]

Thank you Monique I'm not expecting anything greater than that before midnight so we'll return to Charlie's Snooker Calculator with a more tricky one in a later round.

And meanwhile move on with...

Round 313 - Smiley faces

Place two snooker balls - one white and one blue - on a table, touching each other, with the white on the left of the blue.

Now draw a smiley face with a marker pen on the white ball, facing you (if you look at the snooker balls while standing away from the table, with them at your eye level) - like in the picture attached.

Then, holding the blue ball still, roll the white ball up and over the blue ball and then back down the other side, so the white finishes back on the bed of the table, still touching the blue, on the blue's right hand side. The white and blue should remain in contact at all times, with the white rolling and not slipping, so the white rolls along half the circumference of the blue (and the blue never moves at all).

Which way is the smiley face facing now, and which way up is it?

Answers on the thread please... and you are not allowed to try it, before answering, using real snooker balls or anything else to represent the balls - just all in your imagination!

[Monique]

red 1
+ 1
red 1
+ 2
red 1
+ 3
red 1
+ 4
red 1
+ 5
red 1
+ 6
red 1
+ 7
red 1
+ 8
red 1
+ 9
red 1
+ 10
red 1
+ 11
red 1
+ 12
red 1
+ 13
red 1
+ 14
red 1
+ 15
yellow 2
x 30
green 3
x 90
brown 4
X 360
blue 5
x 1800
pink 6
x 10800
black 7
(x)= 75600

[davis_greatest]

Round 312 - Incalculable Charlie

Charlie has just been given an early Valentine's gift from a secret admirer - it is a Simple Snooker Calculator.

The Simple Snooker Calculator has 15 red buttons, one yellow button, one green, one brown, one blue, one pink and one black - each of which he may press once and once only.

Pressing a red button makes "1" appear, and the other coloured buttons make 2, 3, 4, 5, 6 or 7 appear according to the respective values of coloured balls in snooker.

The Simple Snooker Calculator also has five white buttons: labelled +, -, x, / and =. Charlie must always press a white button immediately after pressing any of the coloured buttons (red counts as a colour, white does not).

Pressing +, -, x or / immediately calculates the answer (like pressing an "=" key on a calculator) and then prepares to add, subtract, multiply or divide.

For example, if Charlie presses the following:

red + red + red + red + red + red + red + red + red + red + red + red + red + red + red + black + pink - blue + brown - green x yellow =

then the display will look as follows after each key press:

red 1
+ 1
red 1
+ 2
red 1
+ 3
red 1
+ 4
red 1
+ 5
red 1
+ 6
red 1
+ 7
red 1
+ 8
red 1
+ 9
red 1
+ 10
red 1
+ 11
red 1
+ 12
red 1
+ 13
red 1
+ 14
red 1
+ 15
black 7
+ 22
pink 6
- 28
blue 5
+ 23
brown 4
- 27
green 3
x 24
yellow 2
= 48

which is just the calculation:
(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+7+6-5+4-3)x2 = 48


Post here on the thread the greatest final value you can find for Charlie after pressing the = key. You can post as many as you like, as long as each one you post is higher than the previous one you posted.

You should state not only the final value on the display, but the keys pressed to get it. (You may state the keys in the same format as the example in bold blue type above.)

And hurry... this is all about speed. The round will close with the greatest final value posted here before midnight UK time tonight (or when the first answer appears, if there are no answers before midnight).

[PaulTheSoave]

I think those submitted past the deadline should be iin contention for disqualification and the one submitted before the deadline is good enough for second prize. .

[davis_greatest]

Its late, so this could be totally wrong, but have a try.

5 reds = 5
black = 12
2 reds = 14
black = 21
red = 22
black = 29
2 reds = 31
black = 38
red = 39
black = 46
red =47
pink = 53
red =54
blue = 59
2 red = 61
black = 68
1 red = 69
1 blue = 74

free ball at start

Congratulation, PaulTheSoave, on winning the round, with the highest Indivisible break submitted before the midnight deadline! Well done!

one more now (out of contention, just for the fun of it), think it is 97 now:

black-7
2 reds-9
black-16
red-17
black-24
red-25
blue-30
red-31
black-38
red-39
black-46
red-47
blue-52
red-53
blue-58
red-59
black-66
red-67
pink-73
red-74
blue-79
3reds-82
pink-88
red-89
pink-95
yellow-97

... and congratulations, snookersfun, for submitting a number of Indivisible breaks, both before and after the deadline, including this one, the highest submitted, but out of time.

[PaulTheSoave]

Just a little tester on your snooker knowledge. ahum!

Still waiting for the cheer, champagne, chocolates and flower bouquet. .

almost did my head in with 4 minutes left, and not that clear because of some wine

No, see post 2812, R. 310, and maximum discussion thread....

[snookersfun]

Does the free ball black not count as 1 then instead of 7?

No, see post 2812, R. 310, and maximum discussion thread....