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Originally Posted by davis_greatest View PostSo... that's good for 121... and is the leading (and only) bid!
PS I haven't even thought about this question yet and what a good bid might be yet - but I shall do.... I feel sure that much higher is possible!
... edit - or perhaps not? We'll seetheoretically 126 would be the highest achievable, wouldn't it? but I don't think one can avoid having the 5 '2pointers'.
OK, R. 302 is crazy, a one time through now (and I am sure higher is possible): 231
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Originally Posted by Monique View PostX_X_X_X_X_X_X
_X_X_X_X_X_X
X_X_X_X_X_X_X
______X
PS I haven't even thought about this question yet and what a good bid might be yet - but I shall do.... I feel sure that much higher is possible!
... edit - or perhaps not? We'll seeLast edited by davis_greatest; 24 January 2008, 06:52 PM.
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Originally Posted by Monique View PostRound 301: bid of 121
And if anyone else wants to bid, please do!
Any bids for round 302? At the moment, a bid of 3 could win it!
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Originally Posted by Deano82 View Postman your a hard person to please
ok try this brown + 3 reds top left green + 4 reds top right
(4) (5)
yellow + 4 reds bottem left blue + 3 reds bottom right
(5) (4)
Congratulations Deano82 on being the 30th member to be admitted to the Puzzles with numbers and things Hall of Frame, and also to abextra, snookersfun and Monique who gave the maximum bid also to round 300, and to dantuck_7 who gave a high but not-as-high bid:
So here is the Puzzles with numbers and things Hall of Frame
Oliver (my pet orang-utan)
Gordon (my pet gorilla)
Charlie (my pet chimpanzee)
snookersfun
abextra
davis_greatest (Oliver's, Gordon's and Charlie's pet something)
Vidas
chasmmi
elvaago
robert602
Sarmu
The Statman
austrian_girl
austrian_girl's dad
Semih_Sayginer
Snooker Rocks!
Ginger_Freak
April Madness
steveb72
rambon
Microsoft Excel
dantuck_7
berolina
Parklife Ricky
oddyseus
Monique
moglet
Stella147
PaulTheSoave
Deano82
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Originally Posted by davis_greatest View PostHehe. ... but it is the number of balls that should balance, not the value of balls - otherwise the table will topple.
For example, if you have 5 balls in the two top pockets combined, you must have 5 balls in the two bottom pockets combined...
man your a hard person to please
ok try this brown + 3 reds top left green + 4 reds top right
(4) (5)
yellow + 4 reds bottem left blue + 3 reds bottom right
(5) (4)
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Originally Posted by dantuck_7 View PostI was probably hallucinating - but I thought I read that no answer above 110,000 was possible.
Your bid was good too.... just not the highest possible.Last edited by davis_greatest; 23 January 2008, 10:51 PM.
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Originally Posted by davis_greatest View PostOK... nearly enough for the Hall of Frame entry ... but which pockets are the top pockets and which are the bottom ones? (Remember they must balance.)
I was probably hallucinating - but I thought I read that no answer above 110,000 was possible.
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Originally Posted by Deano82 View Postas for 301. i think 42 as no matter how you put them just adding them will always come to 42 ?
But if you arrange them in other ways, you can have balls being part of more than one Line, and so score more!
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Originally Posted by Deano82 View Post8 and 6 at 1 end and 2 7's at the other lol
i just copied the list from another post then edited a bit with balls but forgot to put in correct order
For example, if you have 5 balls in the two top pockets combined, you must have 5 balls in the two bottom pockets combined...
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as for 301. i think 42 as no matter how you put them just adding them will always come to 42 ?
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8 and 6 at 1 end and 2 7's at the other lol
i just copied the list from another post then edited a bit with balls but forgot to put in correct order
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Surely for 301, the ideal solution would be of some sort of hexagonal/triangular structure, containing the 21 balls.
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