Puzzles with numbers and things

[Monique]

I go for 405!

[snookersfun]

Thought it would be!

301 grapes can still be beaten

yeah, well 400

[April madness]

Are those grapes sour? Cos if they were sweet, you'd eat them, not beat them

[davis_greatest]

270 is the equilateral triangle.

Thought it would be!

301 grapes can still be beaten

[Monique]

270 is the equilateral triangle.

[davis_greatest]

thought I would be with these again:
http://www.thesnookerforum.com/showp...postcount=2218

Very nice... so 301 is leading bid at the moment

[snookersfun]

thought I would be with these again:
http://www.thesnookerforum.com/showp...postcount=2218

[davis_greatest]

R236 grapes

Let's see the arrangements for the 270 and the 301, before the next bid please

[snookersfun]

to those grapes now: 301?

[snookersfun]

Round 237: square clusters of balls (still snooker, am I doing good or what?)

On a 12x12 grid you are supposed to arrange square clusters of snooker balls (1, 2x2, 3x3, etc.). The numbers at the sides indicate the numbers of balls in each respective row or column. Again no touching of clusters (or rather their square outlines) not even diagonally.
cueimages10 018.jpg

answers initially to me

[snookersfun]

morning news:
Monique solved R235 a long while ago. Congratulations!

the 25 pineapples luckily popped into my head at some point yesterday as well, after freeing my head from another battle, which will come up in a few seconds... Still haven't thought about grapes though

[davis_greatest]

Ok first bid 270 grapes ...

Nice opening bid... so, it's in the lead! (and ready to be outbid )

[Monique]

Ok first bid 270 grapes ...

[davis_greatest]

and, it had to come eventually...

R236 - Touching Grapes

Same rules as Rounds 231, 232 and 234, but add up the points scored by all your balls, and that is the number of grapes you can claim.

Please post here the number of grapes you are claiming. Once we have some decent claims, I will then ask you to explain where you placed your balls.

[davis_greatest]

Build a star with 5 "legs" of four balls each around a central ball. This way all the 21 balls are taken into account and the central ball "weights" 5. You cannot do better because you can only put 6 balls maximum "around" one central ball. But if you do that you have only three lines, not 5, because opposite legs are aligned. So the central bal weights only 3 and the total is then 23.

D_G please revise the english ... Not sure it is understandable

Perfectly understandable... and correct, of course! Congratulations on the 25 pineapples!
The central ball, of course, scores 25, as it appears in 5 lines of 5 balls.