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Originally Posted by Lee Vilenski
How did you get 7? But do keep going... it is quite a bit bigger than that... 
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How did you get 7? But do keep going... it is quite a bit bigger than that...
"If anybody can knock these three balls in, this man can."
David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television. -
Edit, Sorry, I meant 79Comment
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Originally Posted by Lee Vilenski OK... still bigger....
"If anybody can knock these three balls in, this man can."
David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.Comment
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Wow. Do you have to use the wieght? Because it would help if I knew how much a snooker ball wieghed.Comment
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You have to use the fact that (in this puzzle) every ball weighs the same and every one weighs a whole number of grams.Originally Posted by Lee Vilenski
And, another clue... a snooker ball weighs much more than 1 gram and much less than 1 kg. You don't need any more info than that...
"If anybody can knock these three balls in, this man can."
David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.Comment
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So if you've got, 147.899kg then you have 147,899 grams. You also have to find a (triangular number -1)*2. Triangle Numbers are 1, 3, 6, 10, 15 ect. So I'm looking for a number that , 0, 2, 5, 9 ect.
Am I on the right lines?Comment
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Yes, 147899 grams and yes, you're on the right linesOriginally Posted by Lee Vilenski
Yes, the number of balls in each "triangle" (with one ball missing) could be 2, 5, 9 etc. Remember there are 2 triangles, so there will be twice as many balls as that. And then all the balls are placed in a rectangle, longer that it is wide, but as wide as possible.
You need to find the factors of 147899. Then one row of balls weighs 147899 grams, so the number of balls in a row of the rectangle is.... ?"If anybody can knock these three balls in, this man can."
David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.Comment
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Right well you can't divide 147899 by any integer, well, I couldn't find one, so, let me guess, it was just one long line of balls?Comment
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Haha... of course you can!Originally Posted by Lee Vilenski
Edit: I just found this site, which might help you...
http://www.btinternet.com/~se16/js/factor.htm"If anybody can knock these three balls in, this man can."
David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.Comment
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lol guys!
Lee, did you find the factors yet?
I shall wait with putting up the answer...Comment
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131 by 1129. So then, I have to find the number of balls left in the Rectangle. So, we have 1129 balls, from 1 line. So, The number of balls in the rectangle has to be even.Comment
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Round 163.... OK, I've had some right and some wrong answers... for those still trying, here are some more (big) clues:
If a triangle has n rows, then it has n(n+1)/2 balls.
(For example, a triangle of reds in snooker has n=5 rows, and 5 x 6 / 2 = 15 balls.)
Now each "triangle" has 1 ball missing, so it has
n(n+1)/2 - 1
= (n² + n - 2)/2 balls
So the two "triangles" (each with a ball missing) comprise (n² + n - 2) balls in total.
We can factorise this as
(n² + n - 2) = (n - ?)(n+ ?)
So there are ??? rows of ??? balls each...."If anybody can knock these three balls in, this man can."
David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.Comment
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Ah yes!
(n2 + n - 2) = (n - 1)(n+2)Comment
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And so... what is the answer to the original question?Originally Posted by Lee Vilenski
OK, someone please, post it. Time to move on....
"If anybody can knock these three balls in, this man can."
David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.Comment
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1129???????Comment
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