Puzzles with numbers and things

[snookersfun]

For those who have found the 106 break, another little challenge below (in hidden text - select it to read)...

think I have a 109 now

[snookersfun]

Morning news flash

Abextra has solved R240 (in fact got a smiley solution yesterday evening)
Well done
Monique meanwhile hasn't given up on R237. That's the spirit!

R 233 and R 235 should be closed soon though. Robert, d_g, Dan, Semih, anybody?? Anything to put up on the thread? Otherwise the ladies' solutions will come up by tomorrow...

[Semih_Sayginer]

only thing ive got to put on here is:-

thank you

your puzzles are fun!

[snookersfun]

update R237

Monique persevered and joined the club! Hurray! Very well done!!!

[davis_greatest]

and update to R241...

Those who have already submitted breaks (i.e. snookersfun and Monique), please put up the descriptions of the breaks any time after 10a.m. BST tomorrow

And if anyone else who wants to do it before then, please post any break and description directly on the thread any time from now.

[davis_greatest]

Another R241 update...

abextra has eased in also with a 109 break! As she hasn't put it up here yet though, there's still about 8 hours for anyone else to put up a break (and how it is made) here

[Monique]

Ok here is the 106: pot 3 reds together, then black-red-black ... until exhaustion of reds. You can't pot the yellow for 108 as you had 10 and 98 as previous intermediate break.

[dantuck_7]

My PC didn't even get a century - only a 70 break - rubbish hey!

[snookersfun]

My PC didn't even get a century - only a 70 break - rubbish hey!

lol Dan! What did you tell him to do?

OK, that 109:
2 reds to start out, green, all remaining reds with blacks (no colours possible again, due to that 2 break at the beginning)

and here are the solutions to R.233 and 235 courtesy to Abextra and Monique (actually to me, as I couldn't open Monique's properly):
6ljsjlw.jpg
desktop.jpg

[snookersfun]

237 and 240 can come up on the thread now as well...

that means I can put up R. 242: back to hexagons:

regular fleet, this time the hints point to total number of parts as a sum of 2 lines each.

desktop1.jpg

answers to me, any option

[vuce]

I'd very much like to see that 237 solution... This says there isn't one :>

[snookersfun]

I'd very much like to see that 237 solution... This says there isn't one :>

lol again. These computers, of course you lost me after about line 10 of 'This', but I might as well put up the solution here now, solved independently by 3 people: d_g, Monique and myself...

adr147a.jpg

[vuce]

lol again. These computers, of course you lost me after about line 10 of 'this', but I might as well put up the solution here now, solved independently by 3 people: d_g, Monique and myself...

[ATTACH]894[/ATTACH]

thanks, that explains things. I thought there has to be only one 1x1 and one 2x2 and so on.

[snookersfun]

thanks, that explains things. I thought there has to be only one 1x1 and one 2x2 and so on.

oh, no... as many as needed.... sorry if that wasn't clear

But don't let that discourage you and your programs from doing the next puzzles

[davis_greatest]

thanks, that explains things. I thought there has to be only one 1x1 and one 2x2 and so on.

Indeed it would have been impossible had that been the case. The rows (or columns) all sum to 61. So if you had 5 squares (1x1 + 2x2 + 3x3 + 4x4 + 5x5) they would not add up to enough; and if you had 6 or more, they would add up to too much!