Scoreboard after round 65
With the deadlines for Bigger Ape Break and Smaller Ape Break expired, below is the confirmed scoreboard.
snookersfun and abextra are invited to post their solutions showing how a break of 199 can be achieved in Bigger Ape Break - this is the maximum possible.
snookersfun, chasmmi and abextra are invited to post their solutions showing how a break of 154 can be achieved in Smaller Ape Break - again, the maximum possible.
HERE IS THE SCOREBOARD AFTER ROUND 65
snookersfun……………………….…..30
abextra……………………………..…...16
Vidas……………………………………….12½
davis_greatest…………………..……12½
robert602…………………………………6
elvaago...............................5
The Statman……………………..……3
chasmmi ………………………………….3
Semih_Sayginer.....................2½
(some rounds may be worth more than one point)
(especially ones won by davis_greatest)
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Gordon, Charlie and Oliver all understood it perfectly too.
I couldn't understand a word.
Edit: this was referring to the post with letters mixed up - not to snookersfun's question which appeared at the same time.
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an easy one for in between...
Suppose you had a bag with 600 red snooker balls and would at each turn randomly take 15 of them and mark them. At the best case scenario (choosing only unmarked balls) it is clear that one could mark all balls after 40 turns. But picking the balls randomly (or blind) how many balls would be probably marked after 40 turns and how many turns would one need to mark 90% of the balls.
Excel solutions worth 1/2 point, others 1 point. (by PM)
Deadline Tuesday-12:00 pm (GMT)
Everybody hold his/her horses, we are rewording!
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Originally Posted by abextraThe phaonmneel pweor of the hmuan mnid.
I cdnuolt blveiee taht I cluod aulaclty uesdnatnrd waht I was radneig. Aoccdrnig to a rscheearcr at Cmagbride Uinervtisy, it deosn't mttaer in waht oredr the ltteers of a wrod are, the olny iprmoatnt tihng is taht the frist and lsat ltteer be in the rghit pclae.The rset can be a taotl mses and you can sitll raed it wouthit a porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe. Amzanig, huh?
Isn't it funny, that I can easily understand this text and at the same time I'm not able to see difference between names Oliver and Charlie?Could read your text easily as well. We would now need some feedback from male subjects on this.
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Originally Posted by davis_greatestExcept Charlie isn't playing! It's Gordon and Oliver.
I cdnuolt blveiee taht I cluod aulaclty uesdnatnrd waht I was radneig. Aoccdrnig to a rscheearcr at Cmagbride Uinervtisy, it deosn't mttaer in waht oredr the ltteers of a wrod are, the olny iprmoatnt tihng is taht the frist and lsat ltteer be in the rghit pclae.The rset can be a taotl mses and you can sitll raed it wouthit a porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe. Amzanig, huh?
Isn't it funny, that I can easily understand this text and at the same time I'm not able to see difference between names Oliver and Charlie?
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Originally Posted by snookersfunwell done Abextra!16% of a banana!
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Round 63 and round 64 update
With abextra now having submitted the maximum breaks possible to both Bigger Ape Break and Smaller Ape Break a few minutes ago, she has now secured 2 points for each of these two rounds, thus jumping a meteoric 4 points in a matter of minutes...
SO HERE IS THE SCOREBOARD AFTER ROUND 65, BUT BEFORE THE CONCLUSION OF ROUNDS 63 AND 64 (with snookersfun’s, chasmmi’s and abextra's points scored so far on these rounds already included)
snookersfun……………………….…..30
abextra……………………………..…...16
Vidas……………………………………….12½
davis_greatest…………………..……12½
robert602…………………………………6
elvaago...............................5
The Statman……………………..……3
chasmmi ………………………………….3
Semih_Sayginer.....................2½
(some rounds may be worth more than one point)
(especially ones won by davis_greatest)
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Originally Posted by abextra....then Charlie wins the games with 17, 18, 19 and 20 ....
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That's right - well explained. Gordon wins the first 2 games. Then Oliver wins 4, then Gordon wins 4, Oliver wins 4... etc, until Gordon reaches 10 with the score 10-8.
Each time an ape can take one, two or three balls. The first ape should try to ensure that the number of balls remaining for the second ape will be 1 more than a multiple of 4, i.e. should try to leave 1, 5, 9, 13, 17, 21, etc
Then, however many balls the 2nd ape takes each time, the first ape should always leave again 1 more than a multiple of 4 - he can do this by taking 4 minus the number of balls just taken (so if 1 was taken, he takes 3; if 2 were taken, he takes 2; if 3 were taken, he takes 1).
Therefore, the starting ape will always win the game unless the number of balls to start with is 1 more than a multiple of 4, which happens every 4th game.
Game 1: 15 balls to start. Gordon takes 2 in his first turn, to leave 13. However many Oliver then takes, Gordon leaves 9. Then Gordon leaves 5. Then leaves 1 - Gordon wins
Game 2: 16 balls to start. Gordon takes 3 in his first turn, to leave 13 - Gordon wins as before
Game 3: 17 balls to start. However many Gordon takes, Oliver can make sure that he leaves 13 for Gordon. -> Oliver wins and starts the next game
Game 4: 18 balls to start. Oliver takes 1 ball to leave 17. -> Oliver wins
etc
Game 1: 15 balls to start. Gordon wins.
Game 2: 16 balls to start. Gordon wins.
Game 3: 17 balls to start. Oliver wins.
Game 4: 18 balls to start. Oliver wins.
Game 5: 19 balls to start. Oliver wins.
Game 6: 20 balls to start. Oliver wins.
Game 7: 21 balls to start. Gordon wins.
Game 8: 22 balls to start. Gordon wins.
Game 9: 23 balls to start. Gordon wins.
Game 10: 24 balls to start. Gordon wins.
Game 11: 25 balls to start. Oliver wins.
Game 12: 26 balls to start. Oliver wins.
Game 13: 27 balls to start. Oliver wins.
Game 14: 28 balls to start. Oliver wins.
Game 15: 29 balls to start. Gordon wins.
Game 16: 30 balls to start. Gordon wins.
Game 17: 31 balls to start. Gordon wins.
Game 18: 32 balls to start. Gordon wins.
So Gordon wins 10-8
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I started with small numbers of balls and found out, that most of times the player who starts the rolling, can win the game. The second player can win only every fourth game, when there are 4n+1 balls on the table (n= 1, 2, 3, ... ). It means, if Gordon starts the match, he wins the first two games with 15 and 16 balls on the table, then Charlie wins the games with 17, 18, 19 and 20 balls, the next four games will be won by Gordon etc. Gordon will be the first to win 10 games, when Charlie has won only 8, but the difference between them won't be more than 2 wins, no matter how long they will play.
Sorry for my English.
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Updated scoreboard - but with rounds 63 and 64 still open!
Here is an update on the scoring.
Round 61 – Triangle Mad…
We had to find the number of triangles in a snooker table where every pocket has been joined by a straight chalk line (picture at the bottom of this message, courtesy of snookersfun). snookersfun and davis_greatest each found 66 triangles, and are awarded a point each for their efforts. (I don't feel too guilty awarding davis_greatest a point here, as he had to search for the triangles in the same way as anyone else)
Round 62 – Last Ball Loser
I had correct answers by Private Message from snookersfun and abextra, and invite them to paste their answers / explanations here. They each score a point for correctly explaining that Gordon will win by the score of 10-8.
Round 63 Bigger Ape Break and Round 64 Smaller Ape Break are still open until the deadlines of 18:00 and 19:00 GMT respectively tomorrow (Sunday 26 November).
So far, I have had submissions to both these rounds from chasmmi and snookersfun, who gradually increased the breaks they offered.
On Bigger Ape Break, snookersfun has found the maximum break possible and therefore has already scored 2 points. Chasmmi has found a good, but smaller break, and is assured of at least 1 point. If anyone else matches snookersfun’s break by the deadline, that person will also score 2 points.
On Smaller Ape Break, snookersfun and chasmmi have both found the maximum break possible and therefore have each already scored 2 points. Again, anyone who matches them can also score 2 points.
For each of these two round, 1 point will be awarded for what I deem to be a "good" break that is not the maximum possible.
Round 65 – hegeland’s "throwing the snooker ball" physics question:
As davis_greatest doesn’t get that many chances to score points, I’ll award him a point here for correctly answering this question.
HERE IS THE SCOREBOARD AFTER ROUND 65, BUT BEFORE THE CONCLUSION OF ROUNDS 63 AND 64 (with snookersfun’s and chasmmi’s points scored so far on these rounds already included)
snookersfun……………………….…..30
Vidas……………………………………….12½
davis_greatest…………………..……12½
abextra……………………………..…...12
robert602…………………………………6
elvaago...............................5
The Statman……………………..……3
chasmmi ………………………………….3
Semih_Sayginer.....................2½
(some rounds may be worth more than one point)
(especially ones won by davis_greatest)
Analysis: davis_greatest appears to have edged half a point above abextra, but if she scores even 1 point by submitting a "good" break on Bigger Ape Break or Smaller Ape Break, she will leap straight into second place! ... Unless Vidas does tooThis is getting as exciting with the various possibilities as Thursday night's Premier League was (in which Ken Doherty was extremely fortunate to be given a masterclass by Steve Davis totally free of charge
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