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Congratulations elvaago!
That is the correct answer!
Here is the general solution if x is the number of balls in the triangle:
When x is divisible by 3, the fewest number of balls that must be moved is x/3.
When x is not divisible by 3, the fewest number of balls that must be moved is (x-1)/3.
So for 15 balls in the triangle, you must move 5 balls.
For 55 balls in the triangle, you must move 18.
For 210 balls in the triangle, you must move 70.
In each case, you must move 3 triangles of reds - one from each corner. When the number of rows is one more than a multiple of 3 (for instance, when the number of rows was 10, which is one more than 9, a multiple of 3), then the triangles moved from each corner are the same size! Otherwise, one triangle moved from a corner is a different size to the other two.
I am going to invite abextra to post here the brilliant diagram she sent me by Private Message earlier today.
SO HERE IS THE SCOREBOARD AFTER ROUND 95
snookersfun.........................47
abextra...............................31
davis_greatest.....................23½
Vidas..................................12½
chasmmi..............................12½
elvaago...............................11½
Sarmu..................................8
robert602.............................7
The Statman.........................5
austrian_girl and her dad.........3½
Semih_Sayginer.....................2½
Snooker Rocks! .....................2½
Ginger_Freak.........................1½
April Madness........................1
ROUND 96 ...
... to follow (I think - once I've thought what to ask).
Originally Posted by elvaago
Here is the general solution if x is the number of balls in the triangle:
When x is divisible by 3, the fewest number of balls that must be moved is x/3.
When x is not divisible by 3, the fewest number of balls that must be moved is (x-1)/3.
So for 15 balls in the triangle, you must move 5 balls.
For 55 balls in the triangle, you must move 18.
For 210 balls in the triangle, you must move 70.
In each case, you must move 3 triangles of reds - one from each corner. When the number of rows is one more than a multiple of 3 (for instance, when the number of rows was 10, which is one more than 9, a multiple of 3), then the triangles moved from each corner are the same size! Otherwise, one triangle moved from a corner is a different size to the other two.
I am going to invite abextra to post here the brilliant diagram she sent me by Private Message earlier today.
SO HERE IS THE SCOREBOARD AFTER ROUND 95
snookersfun.........................47
abextra...............................31
davis_greatest.....................23½
Vidas..................................12½
chasmmi..............................12½
elvaago...............................11½
Sarmu..................................8
robert602.............................7
The Statman.........................5
austrian_girl and her dad.........3½
Semih_Sayginer.....................2½
Snooker Rocks! .....................2½
Ginger_Freak.........................1½
April Madness........................1
ROUND 96 ...
... to follow (I think - once I've thought what to ask).
) on the thread.
I guess it depends from which end you are looking at the table. The diagram shows the view that the ape breaking off would have. 
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