18 is my first impression.....14*red-pink, 1*red-brown-yellow, a green-brown, (these 16 contributions are shared by players A & B), then A pots both pink and blue to go 7 ahead, B pots the the final black, and a respotted black.....=18 breaks of 7!
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Eighteen is absolutely the correct answer. I fiddled with it and I believe it cannot be done in a frame without any fouls.
Now, I have a bit of a predicament because Odrl came up first with the correct answer of 18 whereas JIMO96 was the first to demonstrate it with a relevant sequence.
I think I have to be fair and say that, as I merely asked for an answer and did not require any workings, I have to give the point ot Odrl but I am happy to also award JIMO96 an honorary half-point for his efforts.
Meanwhile, anyone got a next question?
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Stephen Hendry, Steve Davis, Ronnie O'Sullivan, John Higgins, A, B, C, John Spencer, Cliff Thorburn, Terry Griffiths, X, Y, Z.
Who are A, B, C, X, Y, and Z? And if you get it, please explain why.If you want to play the pink, but you're hampered by the red, you could always try to play the brown!
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This thread has been dormant for very very nearly a whole year so it's time to revive it and I'm going to revive it with an easy question:
A player, with a one-point lead, can see the ball on directly, full in the face with no obstruction. He fails to hit the ball on, and yet the referee does not call a Miss.
Why?
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Originally Posted by The Statman View PostThis thread has been dormant for very very nearly a whole year so it's time to revive it and I'm going to revive it with an easy question:
A player, with a one-point lead, can see the ball on directly, full in the face with no obstruction. He fails to hit the ball on, and yet the referee does not call a Miss.
Why?
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