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Player has a free ball on the last red and nominates yellow as his free ball. He then strikes yellow first but goes on to pot both red and the yellow, scoring two points. He then takes the yellow as his colour, which is then spotted to be potted as the first of the six colours.
The only way is this...player B fouls with one red left on table in jaws of pocket but leaving player B a free ball. Yellow is directly in line with red over pocket.
Player A nominates yellow as his free ball and pots BOTH red and yellow (2 points), then takes yellow as his nominated colour after potting a red and then takes his third yellow as part of the colours
The only way is this...player B fouls with one red left on table in jaws of pocket but leaving player B a free ball. Yellow is directly in line with red over pocket.
Player A nominates yellow as his free ball and pots BOTH red and yellow (2 points), then takes yellow as his nominated colour after potting a red and then takes his third yellow as part of the colours
Terry
Terry, why do you say red as to be in the jaws,surely it can be anywhere on the table, apologies if i have misinterpreted you.
I set it up that way as it's the easiest to visualize and also since that is the most common occurance where a player pots 2 balls.
Of course the last red can be anywhere on the table but to get the 3 yellows in a row the play MUST pot both yellow and red on the first shot.
The red being over the pocket is the easiest way to do it unless you happen to be a very expert billiards player or can judge cannons, plus it wouldn't be a fluke on the red if it's in the jaws.
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