can anybody work out and list the possible number of ways there are to make a break of 5? (my highest break), excluding a free ball. I have racked my brains and come up with a number im pretty sure is correct, although im not 100% sure.
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a break of 5?
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1 five reds
2 three reds, yellow
3 two reds, green
4 two reds, yellow, red
5 red, brown
6 red, green, red
7 red, yellow, yellow
8 red, yellow, two reds
9 yellow, green
10 blue
Then there are those positions when a player misses a colour after a red, and the balls are replaced and this time he hits and post (probably flukes) it:
11 brown, red
12 green, two reds
13 yellow, three reds
14 yellow, red, yellow
(and blue, but that's the same as no.10).
Any advance?
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14? Below I think is a complete list of all mathematical possibilities, I've greyed out the ones I don't think are possible in snooker and there are 14 left.
1,1,1,1,1
2,1,1,1
1,2,1,1
1,1,2,1
1,1,1,2
1,2,2
2,1,2
2,2,1
2,3
3,2
3,1,1
1,3,1
1,1,3
4,1
1,4
5
(The odd looking ones that involve starting a break on a colour, then potting reds are legal if you're on a colour, you miss, your opponent has the balls replaced and you pot the colour. Not sure whether you considered those ones or not)
Edit: Statman got there first, but I'm pretty sure we've both covered all the options.
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This has probably been asked been before but what is the answer for the general case. So how many possible ways are there are a break of n?
Is there a pattern (so from normal play):
1,2,3,4, 5, 6
1,2,3,4,10,?
If balls are replaced after a miss:
1,2,3, 4, 5, 6
1,2,4,7?,14,.....
Any ideas?
Dan.
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Originally Posted by The Statman1 five reds
2 three reds, yellow
3 two reds, green
4 two reds, yellow, red
5 red, brown
6 red, green, red
7 red, yellow, yellow
8 red, yellow, two reds
9 yellow, green
10 blue
Then there are those positions when a player misses a colour after a red, and the balls are replaced and this time he hits and post (probably flukes) it:
11 brown, red
12 green, two reds
13 yellow, three reds
14 yellow, red, yellow
(and blue, but that's the same as no.10).
Any advance?
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Originally Posted by RaNeNThis seems to be funny! A break of 5 and so many ways to make it!---
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Originally Posted by The Statman1 five reds
2 three reds, yellow
3 two reds, green
4 two reds, yellow, red
5 red, brown
6 red, green, red
7 red, yellow, yellow
8 red, yellow, two reds
9 yellow, green
10 blue
Then there are those positions when a player misses a colour after a red, and the balls are replaced and this time he hits and post (probably flukes) it:
11 brown, red
12 green, two reds
13 yellow, three reds
14 yellow, red, yellow
(and blue, but that's the same as no.10).
Any advance?
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Originally Posted by snookerelvisThe answer i had was 10 possible ways as listed above, i didnt realise you could start a break off on a colour (forgive my ignorance). if a player fouls on a colour after a red, can a miss be called? and if so shouldnt he be starting off on a red again?
But if the Miss was replaced, then he's got to retake the shot at the colour.
Think of it this way: The most likely reason a player would foul a colour after a red would be because he is snookered on all colours by reds. If the balls are replaced, it would be silly for him to play for a red, since he can obviously see reds. He is being penalised for failing to escape a snooker (which he got hinself into) – so he must now go for a colour again (he may choose another if he likes). If he flukes it, he will be credited with the relevant points and continue on a red.
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Great question that one. I came across the same question in a pub quiz. We were told the answer was "5 ways"...(the clowns). As The Statman correctly points out, there are many more...however I only reached the original 10 ways as listed above.
Surely the 14 combinations as listed by The Statman are the only ones possible? If there are any more, I'll eat my cue, 15 reds and all the colours to boot. Then I'll guzzle down a match play table for desert.
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Originally Posted by HarperSurely the 14 combinations as listed by The Statman are the only ones possible? If there are any more, I'll eat my cue, 15 reds and all the colours to boot. Then I'll guzzle down a match play table for desert.
Enjoy your meal
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Originally Posted by HarperGreat question that one. I came across the same question in a pub quiz. We were told the answer was "5 ways"...(the clowns). As The Statman correctly points out, there are many more...however I only reached the original 10 ways as listed above.
Surely the 14 combinations as listed by The Statman are the only ones possible? If there are any more, I'll eat my cue, 15 reds and all the colours to boot. Then I'll guzzle down a match play table for desert.
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