Puzzles with numbers and things

[Monique]

Here is it again... it's the same as the one I deleted I'm not quite awake today!

155=((7+7+2-1)*2 +1)*5
147=7*7*3
100=5*5*4

[davis_greatest]

Round 368 - update

snookersfun, congratulations on your bid, which works!

Monique - please check yours - your 2nd colour seems to break the rules? You can't pot black as your 2nd colour, because you would have scored 7 points with blacks at that point, which exceeds the points you have by then scored with the other lower valued colours. Edit after Monique's post below: that previous sentence should read: "You can't pot pink as your 2nd colour, because you would have scored 6 points with pinks at that point, which exceeds the points you have by then scored with the other lower valued colours."

Just waiting for abextra once ready to post her list of colours...

... and of course anyone else who wants to put up a bid!

[Monique]

it's not the second, it's the third ... having potted yellow and pink first. That's 8. BTW .. I start with a free ball there.

[davis_greatest]

it's not the second, it's the third ... having potted yellow and pink first. That's 8. BTW .. I start with a free ball there.

Oh sorry - I meant pink, rather than black. But you can't pot pink as second colour either, because pink is worth 6, which exceeds the value of your first yellow (2).

[Monique]

Sorry. I didn't read properly. I thought that rule applied also only from third colour on. My mistake.

[davis_greatest]

Meanwhile, update from round 369 - correctly solved so far by snookersfun and Monique - congratulations.

Rounds 368 and 369 both still open.

[moglet]

R368

Two more bids here

Without free ball 755,467,267,267,367 (122) With free ball 755,637,247,267,267,4 (123)

[davis_greatest]

Thanks moglet! Unfortunately you can't start with a black because then you would have scored 7 points with blacks after the first colour .... the total value of all lower-valued colours potted by that point would be 0 - and that isn't allowed as 7 exceeds 0.

[moglet]

Thanks moglet! Unfortunately you can't start with a black because then you would have scored 7 points with blacks after the first colour .... the total value of all lower-valued colours potted by that point would be 0 - and that isn't allowed as 7 exceeds 0.

Whoops!, will try again.....

[moglet]

R368

Would this do:

223,765,764,752,764,7 (123)

[moglet]

R369

Are Brackets OK?:

5x5x4=100,7x7x3=147,(2x7)x(7+5-1)+(2-1)=155

[Monique]

R368

Hope I didn't mess it up this time ...
2,2,4,7,6,5,7,6,3,7,5,6,7,2,4,7 and the colours for 123

[abextra]

Round 369 - Countdown Breakdown

Use the 13 snooker balls below, and any combination of addition, subtraction, multiplication or division to make the following three target snooker numbers: 100, 147 and 155.

Oh, another nice round finished before I've even seen it...

Just waiting for abextra once ready to post her list of colours...

... and of course anyone else who wants to put up a bid!

abextra is late again... probably my solution is posted already...
(starting with free ball) 2 2 4 7 6 5 7 6 3 7 5 6 7 2 4 7
or 2 2 3 7 6 4 7 6 5 7 2 6 7 5 4 7
+ final colours

[davis_greatest]

Oh, another nice round finished before I've even seen it...

abextra, both rounds are still open - I was just giving an update of who had answers in already.

[davis_greatest]

Round 368 update

Would this do:

Yes, moglet! Congratulations!

Hope I didn't mess it up this time ...

This one is fine! Congratulations!

...(starting with free ball) ...

abextra, your first answer is good, too. Congratulations!
(The second one, however, isn't allowed as it runs into trouble on the 8th colour, I think - as your pinks at that point would exceed yellows+greens+browns+blues. But I'll accept your first answer. )



Round 369 update

Are Brackets OK?:

Yes, they are - since equivalently you can put the balls in any order (they don't have to be arranged from left to right). Congratulations also with your answer!