If this is your first visit, be sure to
check out the FAQ by clicking the
link above. You may have to register
before you can post: click the register link above to proceed. To start viewing messages,
select the forum that you want to visit from the selection below.
I still remember you promised to give me 10 points on this quiz!
For 10 points, you'd need to do my ironing!
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
I had a few euros left from my holiday so I decided to invest the money by placing it on a chessboard. The best way, I have found, to guarantee good returns is to place some money in each square, so that the difference between the money in any two adjacent squares (i.e. squares that share a common side) is exactly one euro. So that is exactly what I did.
But then, Oliver, my pet orang-utan, came and took the money that was on one square (8 euro) and Charlie, my pet chimpanzee, came and took the money that was on another one of the squares (22 euro).
Then Gordon, my skint pet gorilla, took all the money that he found on the two main diagonals and blew the lot on a night out with his girlfriend Florence. How much did Gordon spend?
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
Yes he did, abextra! Well done. Gordon spent 210 euros or, in the words of semih, too much.
Since we know that there were squares containing 8 euros and 22 euros, they must have been 14 squares apart, i.e. they must have been in opposite corners (so to get from one to the other, you go 7 squares up/down and 7 squares left/right).
This then fixes all the other squares, so along one diagonal were 8, 10, 12, 14, 16, 18, 20, 22 euros (adding to 120 euros) and along the other diagonal were 15 euros in each square (adding to 8x15 euros = 120 euros also).
So there were 240 euros on the main diagonals - remove the 8 euros and 22 euros taken by naughty Oliver and Charlie, and you get the 210.
Scoreboard to follow...
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
(some rounds may be worth more than one point)
(especially ones won by davis_greatest)
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
"Really?" said Megusalah, upon hearing Yonah's age. "That makes you exactly one year younger than I. Amazing!"
"Well," said Yonah, "the even more amazing thing is that if you add up the digits in my age, the sum is exactly divisible by the number of sons I have."
"Oh?" said Megusalah. "That's not that amazing. Because I can say exactly the same. But how many sons do you have?"
"17," said Yonah. "And you?"
"Exactly the same. 17. And happy anniversary, darling."
What is the youngest that Yonah could be?
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
The age of the younger person had to end in 9 otherwise the sum of the numbers would change by one only.
Then I took into account that each 9 turning into a 0 reduces the sum of the older person by 9, thus 2 nines by 18, which can be offset by the gain of one in the hundreds to loose a 17. Two nines at the end need another 16 to reach a sum of 34 (2x17), therfore only 88 or 97 possible, 88 being the lower possibility.
Next year, after the success of the round robin format at the Grand Prix, they decide to have a round robin format at the Crucible.
It starts with all 32 players playing each other once (round robin style).
Show that, after the round robin matches have finished, you will be able to find 6 players and stand them in a line (one behind the other) in such a way that each player in the line has beaten all the players standing behind him.
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
The age of the younger person had to end in 9 otherwise the sum of the numbers would change by one only.
Then I took into account that each 9 turning into a 0 reduces the sum of the older person by 9, thus 2 nines by 18, which can be offset by the gain of one in the hundreds to loose a 17. Two nines at the end need another 16 to reach a sum of 34 (2x17), therfore only 88 or 97 possible, 88 being the lower possibility.
Good - almost perfect. You should also mention though that 7999 is not possible (despite 7 and 9 also adding up to 16, and 79 being lower than 88) because if the number ends in 999 (but not 9999) then adding one decreases the sum by 26.
"If anybody can knock these three balls in, this man can." David Taylor, 11 January 1982, as Steve Davis prepared to pot the blue, in making the first 147 break on television.
Comment