Puzzles with numbers and things

[chasmmi]

So why is this not just:

So 6,7,8,10,13 pointer gorillas with 7,9,10,11,15 pointers orangs = 2288 kisses
1,2,4,4,5 gorillas with ,2,3,3,4,5 orangs = 272 kisses

= 2560

[davis_greatest]

Congratulations, snookersfun! Perfect! Well done!

So, let's try Round 205 - Affectionate Clarissa

Exactly as round 204, but this time Clarissa stops being so mean, and gives each of her team members 10 hugs, instead of 1.

Again, what is the greatest number of kisses you can arrange?

snookersfun can answer by PM ... anyone else answer on the thread please!

(I will paste snookersfun's answer here on the thread after anyone else has answered it correctly - except of course in the unlikely event that snookersfun should happen to send a wrong answer, in which case it will be pasted here immediately. )

[snookersfun]

yes, well added some unnecessary factors in beforehand, but easiest way to figure it out, is to choose highest possible product sum of hugs by gorillas * sum of kisses by orangs (of course sum of apes=10),

I found that one finds highest # of kisses for splitting the teams evenly into gorillas and orangs, but having the higher valued huggers grouped with the higher valued kissers in one team.

So 6,7,8,10,13 pointer gorillas with 5,7,9,11,15 pointers orangs = 2068 kisses
1,2,4,4,5 gorillas with 1,2,3,3,4 orangs = 208 kisses
grand total of 2276 smooches

[davis_greatest]

2276 better?

Much better! Let's see how you got it!

[snookersfun]

2276 better?

[snookersfun]

right, I just found that out myself

[davis_greatest]

1st bit: 12420

Wow, that's high! It's not possible to get those many kisses, I'm afraid.

[snookersfun]

1st bit: 12420

[davis_greatest]

Still no success at round 202, I see! So it stays open!

At the same time, here is

Round 204 - The Great Ape Summer Escape Wrap Up in Masking Tape Funny Jape Not In Good Shape Summer Party

It’s time for the Great Ape Summer Escape Wrap Up in Masking Tape Funny Jape Not In Good Shape Summer Party!

At the party are plenty of gorillas and orang-utans. You need to divide them into two teams, with each team to consist of 10 apes.

The gorillas like to hug their team members. In fact,

Alphonso gives each of his team members 7 hugs
Boris gives each of his team members 4 hugs
Clarissa gives each of her team members 1 hug
Daisy gives each of her team members 8 hugs
Elisabeth gives each of her team members 10 hugs
Florence gives each of her team members 4 hugs
Gordon gives each of his team members 2 hugs
Horace gives each of his team members 13 hugs
Isaac gives each of his team members 5 hugs
Juliet gives each of her team members 6 hugs

Each time an orang-utan is hugged, he or she kisses the ape who gave the hug. In fact,

Katie gives 1 kiss for each hug she receives
Lisa gives 9 kisses for each hug she receives
Mike gives 5 kisses for each hug he receives
Noel gives 3 kisses for each hug he receives
Oliver gives 11 kisses for each hug he receives
Patricia gives 3 kisses for each hug she receives
Quincy gives 7 kisses for each hug she receives
Romeo gives a whopping 15 kisses for each hug he receives
Sylvia gives 4 kisses for each hug she receives
Tony gives 2 kisses for each hug he receives

You want to make sure there are as many kisses as possible! Bid here on the thread the number of kisses you make happen, and show how you split the teams.

Anyone can bid at any time, as long as your bid is higher than all valid bids before.

[davis_greatest]

Yes, congratulations snookersfun! There are 8 arrangements.

As you say, to choose 3 colours from 4, there are 4 choices of which colour not to use. For each choice of 3 colours, you can have either the arrangement you showed or its reflection in the mirror. So 4 x 2 = 8 arrangements!

[snookersfun]

Round 203 - snookersfun, yes to part a). Congratulations
No to part b) - missing something fundamental there...

oh dear, remembering things only after PC is off today...

so, guess I forgot about the vast choices of colours I was given,
so there should be 4 possible colour combinations (3 out of 4) and each has those 2 options I found before, so now I reach 8 different arrangements already...

[davis_greatest]

Round 203 - snookersfun, yes to part a). Congratulations
No to part b) - missing something fundamental there...

[snookersfun]

part b) erm... maybe 2 exchanging e.g. b and c basically

[snookersfun]

a) 3 different colours
....c
...ab
..bca
.cabc
abcab

thinking about b) still in progress...

[davis_greatest]

Let's have round 203 also, while round 202 is of course still open (and unanswered)...

Round 203 – Rainbow triangle

You are playing with Gordon, my pet gorilla, and have a large collection of blue, yellow, pink and brown snooker balls, and a snooker triangle that can surround 15 balls. You need to help Gordon put 15 balls into the triangle, so that no two balls of the same colour are touching – and you must use the smallest possible number of different colours!

a) How many colours do you use? Show a possible arrangement of the balls.

b) How many possible different arrangements are there (always using as few colours as possible, with no two balls of the same colour touching)?
Note: if the triangle can be rotated (without removing the balls from the bed of the table) from one arrangement to another, they count as the SAME arrangement.

Answers / guesses / funny comments please on the thread!