Puzzles with numbers and things

[abextra]

chasmmi, anyone can simply copy the answer from a post above. You're supposed to work it out for yourself.

davis_greatest, I'm sure chasmmi didn't copy my answer, we posted at the same time exactly!

[davis_greatest]

Ok, Friday: highest break - 27 points

Charlie - red brown red blue red pink red black red
Oliver - red brown red blue red pink yellow green brown
Gordon - red yellow red green yellow green brown blue pink

Congratulations abextra! And shame on you chasmmi
That (together with abextra's earlier post specifying the breaks that my apes made on Thursday) is the correct answer!

On Wednesday, they made breaks of 9, each potting 3 balls. On Thursday, breaks of 18, each potting 6 balls; and on Friday, breaks of 27, each potting 9 balls! And there the pattern ends.

[davis_greatest]

Does this work?

Charlie: RED BROWN RED BLUE RED PINK RED BLACK RED

Oliver: RED BROWN RED BLUE RED PINK YELLOW GREEN BROWN

Gorden: RED YELLOW RED GREEN YELLOW GREEN BROWN BLUE PINK

chasmmi, anyone can simply copy the answer from a post above. You're supposed to work it out for yourself.

[abextra]

Hehehe, that was really close!

[chasmmi]

[expletive deleted] Invisible letter to use up aparent lack of characters.

[chasmmi]

Does this work?

Charlie: RED BROWN RED BLUE RED PINK RED BLACK RED

Oliver: RED BROWN RED BLUE RED PINK YELLOW GREEN BROWN

Gorden: RED YELLOW RED GREEN YELLOW GREEN BROWN BLUE PINK

[abextra]

Ok, Friday: highest break - 27 points

Charlie - red brown red blue red pink red black red
Oliver - red brown red blue red pink yellow green brown
Gordon - red yellow red green yellow green brown blue pink

[davis_greatest]

Round 124

Thursday: highest break - 18 points

Charlie - red brown red blue red pink
Oliver - red blue red pink yellow green
Gordon - red green yellow green brown blue

Are there only two breaks possible? I've found a break of 27 points, but I don't like it very much... Should I keep on trying?

Correct! Those were the breaks made on Thursday!

Indeed, there is (unless I am mistaken) only one possible answer to this question. So let's hear the breaks my apes made on Friday....

[abextra]

Round 124

Thursday: highest break - 18 points

Charlie - red brown red blue red pink
Oliver - red blue red pink yellow green
Gordon - red green yellow green brown blue

Are there only two breaks possible? I've found a break of 27 points, but I don't like it very much... Should I keep on trying?

[davis_greatest]

I'm back! (if anyone noticed I had been away)

Round 124 - Breaking level

On Wednesday evening, my three pet apes, Charlie, Oliver and Gordon went to play snooker. Each pair played one frame – Charlie beat Oliver, then Oliver beat Gordon, then Gordon beat Charlie, so 3 frames were played in all.

Whenever any of my apes is due to pot a colour during a break (after the first colour potted in that break), he will only ever pot a colour worth one point more than the previous colour he had potted during that break – unless he is on the yellow when down to the final 6 colours. For instance, if an ape pots red, blue, red then, for the next colour in that same break, he will pot pink. If, however, he pots the final red and any colour, then he can, of course, only continue with the yellow.

The apes never foul, nor do they ever pot more than one ball in the same shot.

At the end of the evening, Charlie, Oliver and Gordon, each having won one frame, compared their highest breaks. Charlie had a highest break of 9 (red, black, red), as did Oliver (who had potted red, pink, yellow) and, amazingly, so did Gordon (he had potted yellow, green, brown). You will notice that each break consisted of 3 pots. Impressive!

They therefore remarked that:

(a) they had each made the same highest break;
(b) they had each potted the same number of balls in making that break;
(c) in making those breaks, Charlie had potted more reds than Oliver, who had potted more reds than Gordon.


Last night, Thursday, they played again. This time, their highest breaks were higher than on Wednesday, but (a), (b) and (c) above had all happened again, exactly as before.

Tonight, Friday, they just got back from playing another 3 frames. They really enjoy it. Once again, they improved their highest breaks further, but again (a), (b) and (c) all happened.


What balls did each ape pot in making his highest break on Thursday? And tonight?

Your answer should be of the form:
"Thursday: Charlie - red pink red ...(or whatever) ..., Oliver - red yellow... (or whatever) ....., Gordon - pink black (or whatever)....
Friday: Charlie - ...."

[snookersfun]

well done chasmmi and Parklife Ricky (you needed some trial and error, but hopefully not for all the numbers!).

So, welcome to the Hall of Fame Parklife Ricky!

So here is the latest Puzzles with numbers and things Hall of Frame

Oliver (my pet orang-utan)
Gordon (my pet gorilla)
Charlie (my pet chimpanzee)
snookersfun
abextra
davis_greatest (Oliver's, Gordon's and Charlie's pet something)
Vidas
chasmmi
elvaago
robert602
Sarmu
The Statman
austrian_girl
austrian_girl's dad
Semih_Sayginer
Snooker Rocks!
Ginger_Freak
April Madness
steveb72
rambon
Microsoft Excel
dantuck_7
berolina
Parklife Ricky

[Parklife Ricky]

Don't know whether trial and error still really counts as a prove, but nonetheless!

.....106
+19722
+82524
_______
102352

[chasmmi]

1 0 6
1 9 7 2 2
8 2 5 2 4
1 0 2 3 5 2

[snookersfun]

Round 123:

Prove the following by replacing each letter by a number:

........T.W.O
+.T.H.R.E..E
+.S.E.V.E..N
__________
T.W.E.L.V..E

[davis_greatest]

I think there are at least 2 possible answers.

For the first segment you can have:
Four reds, two blues, two pinks (total 26)

For the next segment you can have:
8 reds plus two blacks, two yellows, four greens — plus the following (thirteenth) red. (total 65)

The for the final segment you can have:
yellow, red, green, red, green; followed by the yellow (which satisfies the condition by itself) and the green (which still satisfies the condition).

Total 77 (up to final yellow) or 80 (to final green).

[It is by putting the 13th red at the end of the second segment, rather than at the beginning of the third segment, that means the green condition in the third segment is satisfied without the final green having been played.]

Congratulations The Statman! This (the 77 one), I think, is the only other answer apart from the more obvious 80 one (although I haven't given it a huge amount of thought since noticing that I had not ruled out the possibility of a segment ending in a red, and someone might just find another!).